Fools!
…limiting themselves to Euclidean geometry…Saddle shaped universe confirmed
Looks like a tetrahedron to me.
Exactly! The diagram is simply a schematic.
exactly what I came here to say
That implies one person is observing 3 other people from the above (or flying over), which is not exactly trivial.
Nobody said it would be easy
No one said right angles.
Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.
But its height cannot be half of base because of the same Pythagorean theorem
(1,5)²+(1,5/2)²=2,8125
sqrt(2,8125) ≈ 1,677, which is half of a diagonal
So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture
TL;DR: Won’t work because Pythagorean theorem
Pyramid?
Yes, it is possible with a 3-sided pyramid, i.e. tetrahedron. If we dont look at all 4 points as being on the same plane but 2 opposite corners being offset above or below the other two, this could totally be a tatrahedron.
Wdym?
They could each be on the vertices of a tetrahedron for all we know…
I was thinking of plane surfaces, but if their altitudes are different, I guess it’d be possible.
if the people were aranged in 3d in the shape of a tetrahedron (triangular pyramid) this would work out fine
Well you see, space isn’t flat in this very localized area!
You’re all thinking too two-dimensionally. Clearly the people are being instructed to arrange themselves into a tetrahedron.
Middle one should be the square root of 4.5 meters, or 2.12 meters
Tetrahedrons man, tetrahedrons.
What? Everytime I meet other people we always arange ourselves in the shape of a simplex of the appropriate dimension. Doesn’t everyone?
So the fifth person to arrive moves to the centre of the tetrahedron and shifts roughly 1.299m into the past or future.
I have a few questions.
- How do you attain time offset?
- Doesn’t that make conversation difficult?
- What even is the fifth dimension?
- How do you convert a distance in metres into a distance in time? You would surely then have a universal m/s? Oh, wait, there is a universal speed, it’s the speed of light, which means 1.299m is equivalent to about 4.3 billionths of a second, which is considerably less impressive for question 1 and just not at all problematic for question 2.
- If you’re using very fast motion for your time offset, doesn’t that make conversation even more difficult? How fast would you need to be going to dilate time for a few billionths of a second? Doesn’t Heisenberg uncertainty start to have an impact here? How can you be sure you got it right?
If you have to ask, you wouldn’t understand.
If I understood, I wouldn’t have to ask.
Thank you
